The expression (a+3)2 is an example of a perfect square and expands to a2+6a+9.
The reverse process - taking an expression and creating a perfect square with an additional constant - is called completing the square. This is useful as it gives the turning point of the graph of the function.
Take the expression b2+8b+22:
Halve the coefficient of the b term: 8 ÷ 2 = 4;
Create the squared term from the b and the 4: (b+4);
Expand the squared term: (b+4)2=b2+8b+16;
Add an adjustment (6) to obtain the original expression:
(b+4)2+6=b2+8b+22
The turning point of the quadratic graph is at (-4, 6): the x-coordinate is the value of b that makes the squared term zero; and the y-coordinate is the value of the adjustment.
If the squared term has a coefficient, square root the coefficient and use this inside the bracket. Then divide the x term by that same value; and halve as before:
9x2+30x+13
√9 = 3 to get the coefficient of the x term;
and 30 ÷ 3 = 10 and halved = 5;
Create the squared term: (3x+5);
Expand the squared term (3x+5)2=9x2+30x=25
Add a constant -12 for the original expression:
(3x+5)2-12=9x2+30x+13
Complete the square for 4a2+8a-12
Take the square root of the x2 coefficient: √4 = 2. This is the new x multiplier;
For the integer; divide by the new x multiplier 8 / 2 = 4; then halve 4 ÷ 2 = 2
Obtain (2a+2)2=4a2+8a+4
Add a constant (-16) to obtain the original expression (2a+2)2-16=4a2+8a-12
Answer: (2a+2)2-16
Complete the square for b2-10b
For the integer: half the b coefficient, = -5
Therefore (b-5)2=b2-10b+25
Add a constant -25 to obtain (b-5)2-25=b2-10b
Answer: (b-5)2-25