A vector `((a),(b))` may be a #position vector# which describes a vector from the origin *O* to a point (a, b).

Parallel vectors are vectors that have the same direction but may have different magnitude. In the diagram, below, vectors **a** and **b** are parallel, and **a** = 2**b**. The multiplier is known as a **scalar**.

In the diagram below, points A, B and C are on the same line (they are said to be **collinear**). Vector `vec(AB) = kvec(AC)`, where *k* is a scalar.

Show that points A at (3, 5), B at (7, 11) and C at (13, 20) are collinear.

The explanation as well as the calculation should be provided.

Answer: `vec(AB) = ((4),(6))` and `vec(AC) = ((10),( 15))`

Let `bb(a) = vec(AB)` and `bb(b) = vec(AC)`

`bb(a) = 2.5bb(b)`

**a** is a multiple of **b** and both share at least one point; they are collinear.

Three points are on a straight line AC. Point A is at position (5, 7). Point C is at (-5, 12). Given `vec(AC) = bb(a)` and `vec(AB) = bb(b)`, and `bb(b) = frac(3)(5)bb(a)`, what is the position of point B?

`vec(AC) = ((-10),(5)) `

`vec(AB) = frac(3)(5) xx ((-10),(5)) = ((-6),(3))`

Question asks for the position of point B;

Origin to point A + vector `((-6),(3))` is (5 - 6, 7 + 3) = (-1, 10)

Use a quick sketch if that helps:

Answer: (-1, 10)

Check out our iOS app: tons of questions to help you practice for your GCSE maths. Download free on the App Store (in-app purchases required).