There may be 0, 1 or 2 roots for a quadratic. A root is found for `x` when `f(x)=0`. This can be seen graphically when the curve crosses `y=0`. If the curve does not cross `y=0` then there are no *real roots* for the function.

The roots can be obtained by:

• rearranging as factors; (Factorising)

• using the quadratic formula `x = frac(-b +- √(b^2 - 4ac))(2a)`; (Quadratic Formula)

• completing the square; (Completing the Square)

• deducing iteratively (for a positive square root)

• and for an approximate solution: drawing a graph of the function.

Sketch the graph of `x^2 +4x + 3` showing the coordinates of the roots and the turning point.

Factorise the equation to `(x+3)` and `(x+1)`. This gives the roots as `x=-3` and `x=-1`

The turning point is given using `-frac(b)(2a) = frac(-4)(2(1)) = -2` This is the `x` value, substitute into the original equation for `(-2)^2 +4(-2)+ 3 = 4 - 8 + 3 = -1`

Roots are (-3,0) and (-1, 0); turning point is (-2,-1)

Answer:

The roots of a quadratic are -5 and 7. The turning point is (1, -36). The coefficient of the squared term is 1. What is the quadratic?

The roots give the factors of the expression `(x + 5)(x - 7)`

Multiply that out to give `x^2 - 2x - 35`

Check with the turning point: `-36 = (1)^2 - 2(1) - 35`✔

Answer: `x^2 - 2x -35`

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